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Can you find the product of (1+3i)(2-i)?
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34i
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3-2i
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55i
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5+5i
That's Correct!
It's Wrong!
The product of (1+3i)(2-i) can be found by using the distributive property. First, multiply 1 by 2 and get 2. Then, multiply 1 by -i and get -i. Next, multiply 3i by 2 and get 6i. Finally, multiply 3i by -i and get -$$3i^2$$. Simplifying further, -$$3i^2$$ can be written as -3(-1), which is equal to 3. Combining all the terms, we get 2 + (-i) + 6i + 3, which simplifies to 5 + 5i. Therefore, the correct answer is 5 + 5i.
